HTMLify

class Solution:
    def canAttend(self, arr):
        # 1. Sort the meetings based on start times
        # If start times are equal, it sorts by end times
        arr.sort()
        
        # 2. Iterate through the meetings starting from the second one
        for i in range(1, len(arr)):
            # previous_end = arr[i-1][1]
            # current_start = arr[i][0]
            
            # 3. If the current meeting starts before the previous one ends, 
            # it's impossible to attend all.
            if arr[i][0] < arr[i-1][1]:
                return False
        
        # 4. If no overlaps are found, return True
        return True