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LeetCode - Sqrt(x) - Go
Views: 171 | Author: abh
func mySqrt(x int) int {
for n := range x+1 {
if n*n >= x || (n+1)*(n+1) > x {
return n
}
}
return 0
}
func mySqrt(x int) int {
for n := range x+1 {
if n*n >= x || (n+1)*(n+1) > x {
return n
}
}
return 0
}