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Count Inversions
Views: 14 | Author: prakhardoneria
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class Solution:
    def inversionCount(self, arr):
        def merge_and_count(temp_arr, left, mid, right):
            i = left    
            j = mid + 1 
            k = left    
            inv_count = 0
            
            while i <= mid and j <= right:
                if arr[i] <= arr[j]:
                    temp_arr[k] = arr[i]
                    i += 1
                else:
                    temp_arr[k] = arr[j]
                    inv_count += (mid - i + 1)
                    j += 1
                k += 1
                
            while i <= mid:
                temp_arr[k] = arr[i]
                i += 1
                k += 1
                
            while j <= right:
                temp_arr[k] = arr[j]
                j += 1
                k += 1
                
            for loop_var in range(left, right + 1):
                arr[loop_var] = temp_arr[loop_var]
                
            return inv_count

        def merge_sort(temp_arr, left, right):
            inv_count = 0
            if left < right:
                mid = (left + right) // 2
                inv_count += merge_sort(temp_arr, left, mid)
                inv_count += merge_sort(temp_arr, mid + 1, right)
                inv_count += merge_and_count(temp_arr, left, mid, right)
            return inv_count

        n = len(arr)
        temp_arr = [0] * n
        return merge_sort(temp_arr, 0, n - 1)