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Longest Subarray with Majority Greater than K
Views: 5 | Author: prakhardoneria
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 | class Solution: def longestSubarray(self, arr, k): n = len(arr) prefix_sum = 0 first_occ = {} max_len = 0 for i in range(n): prefix_sum += 1 if arr[i] > k else -1 if prefix_sum > 0: max_len = i + 1 else: if (prefix_sum - 1) in first_occ: max_len = max(max_len, i - first_occ[prefix_sum - 1]) if prefix_sum not in first_occ: first_occ[prefix_sum] = i return max_len |