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LeetCode - Sqrt(x) - Go
Views: 301 | Author: abh
1 2 3 4 5 6 7 8 | func mySqrt(x int) int { for n := range x+1 { if n*n >= x || (n+1)*(n+1) > x { return n } } return 0 } |
1 2 3 4 5 6 7 8 | func mySqrt(x int) int { for n := range x+1 { if n*n >= x || (n+1)*(n+1) > x { return n } } return 0 } |