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LeetCode - Minimum Average of Smallest and Largest Elements - Python
Views: 359 | Author: abh
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class Solution:
    def minimumAverage(self, nums: List[int]) -> float:
        avgs = []
        while nums:
            s, b = min(nums), max(nums)
            nums.remove(s)
            nums.remove(b)
            avgs.append((s+b)/2)
        return min(avgs)