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LeetCode - Count Elements With Maximum Frequency - Python
Views: 378 | Author: abh
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class Solution:
    def maxFrequencyElements(self, nums: List[int]) -> int:
        freq = {}
        h = 0
        for n in nums:
            freq[n] = freq.get(n, 0) + 1
            if freq[n] > h:
                h = freq[n]
        s = 0
        for v in freq.values():
            if v == h:
                s += h
        return s