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LeetCode - Count Common Words With One Occurrence - Python
Views: 2 | Author: abh
1 2 3 4 5 6 7 8 9 10 | # @leet start class Solution: def countWords(self, words1: list[str], words2: list[str]) -> int: count = 0 words = set(words1) for word in words: if words1.count(word) == 1 == words2.count(word): count += 1 return count # @leet end |