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LeetCode - Kth Distinct String in an Array - Python
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1 2 3 4 5 6 7 8 9 10 11 | class Solution: def kthDistinct(self, arr: List[str], k: int) -> str: distinct = [] for c in arr: if arr.count(c) > 1: continue if c not in distinct: distinct.append(c) if len(distinct) < k: return "" return distinct[k-1] |