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LeetCode - How Many Numbers Are Smaller Than the Current Number - Python
Views: 614 | Author: abh
1 2 3 4 5 6 7 | class Solution: def smallerNumbersThanCurrent(self, nums: List[int]) -> List[int]: smallercount = [] sortednums = sorted(nums) for n in nums: smallercount.append(sortednums.index(n)) return smallercount |