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are_anagrams.py
Views: 617 | Author: abh
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 | def are_anagrams(s1, s2): if len(s1) != len(s2): return False for c in s1: if s1.count(c) != s2.count(c): return False return True def are_anagrams(s1, s2): l1 = list(s1) l2 = list(s2) l1.sort() l2.sort() return l1 == l2 def are_anagrams(s1, s2): return sorted(s1) == sorted(s2) |